The number of chlorine atoms present in the organic products $X$ and $Y$ of the following reactions, respectively, are :

![](https://res.cloudinary.com/ddr1kuyb3/image/upload/v1786116331/questions/eug4dcg6yy4myavvqah3.png)

Question

The number of chlorine atoms present in the organic products $X$ and $Y$ of the following reactions, respectively, are :

![](https://res.cloudinary.com/ddr1kuyb3/image/upload/v1786116331/questions/eug4dcg6yy4myavvqah3.png)

Accepted Answer

C. 1. **Identify the two types of reaction an aromatic ring can undergo with Cl₂** — depending on the conditions, chlorine either substitutes a hydrogen (**electrophilic substitution**, needs a Lewis acid catalyst like FeCl₃) or adds across the ring (**free-radical addition**, needs sunlight/UV light, no catalyst).

2. **Analyse the condition used to form product X.**
Given that the reaction proceeds under **sunlight/UV light**, three molecules of Cl₂ add across the three double bonds of the aromatic ring:
$$
C_6H_6 + 3Cl_2 \xrightarrow{h
u} C_6H_6Cl_6
$$
This product, **benzene hexachloride (BHC)**, contains **6 chlorine atoms**.

3. **Analyse the condition used to form product Y.**
Given that this reaction is also carried out under **UV light/sunlight** conditions rather than with a halogen-carrier catalyst, the same free-radical addition pathway operates, again adding three Cl₂ units and giving **6 chlorine atoms** in the product.

4. **Conclusion:** Both X and Y are addition products bearing 6 chlorine atoms each.
Hence, the answer is **Option C**.

The number of chlorine atoms present in the organic products XXX and YYY of the following reactions, respectively, are :

The number of chlorine atoms present in the organic products $X$ and $Y$ of the following reactions, respectively, are :